(4x+3/2x+5)=1

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Solution for (4x+3/2x+5)=1 equation:



(4x+3/2x+5)=1
We move all terms to the left:
(4x+3/2x+5)-(1)=0
Domain of the equation: 2x+5)!=0
x∈R
We get rid of parentheses
4x+3/2x+5-1=0
We multiply all the terms by the denominator
4x*2x+5*2x-1*2x+3=0
Wy multiply elements
8x^2+10x-2x+3=0
We add all the numbers together, and all the variables
8x^2+8x+3=0
a = 8; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·8·3
Δ = -32
Delta is less than zero, so there is no solution for the equation

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