(4x+30)+(2x-10)=80

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Solution for (4x+30)+(2x-10)=80 equation: 



(4x+30)+(2x-10)=80

We move all terms to the left:

(4x+30)+(2x-10)-(80)=0

We get rid of parentheses

4x+2x+30-10-80=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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