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(4x+32)(2x+28)=360
We move all terms to the left:
(4x+32)(2x+28)-(360)=0
We multiply parentheses ..
(+8x^2+112x+64x+896)-360=0
We get rid of parentheses
8x^2+112x+64x+896-360=0
We add all the numbers together, and all the variables
8x^2+176x+536=0
a = 8; b = 176; c = +536;
Δ = b2-4ac
Δ = 1762-4·8·536
Δ = 13824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13824}=\sqrt{2304*6}=\sqrt{2304}*\sqrt{6}=48\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(176)-48\sqrt{6}}{2*8}=\frac{-176-48\sqrt{6}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(176)+48\sqrt{6}}{2*8}=\frac{-176+48\sqrt{6}}{16} $
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