(4x+38)+(6x-48)=180

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Solution for (4x+38)+(6x-48)=180 equation: 



(4x+38)+(6x-48)=180

We move all terms to the left:

(4x+38)+(6x-48)-(180)=0

We get rid of parentheses

4x+6x+38-48-180=0

We add all the numbers together, and all the variables

10x-190=0

We move all terms containing x to the left, all other terms to the right

10x=190

x=190/10

x=19

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