(4x+38)+(6x-48)=180

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Solution for (4x+38)+(6x-48)=180 equation:



(4x+38)+(6x-48)=180
We move all terms to the left:
(4x+38)+(6x-48)-(180)=0
We get rid of parentheses
4x+6x+38-48-180=0
We add all the numbers together, and all the variables
10x-190=0
We move all terms containing x to the left, all other terms to the right
10x=190
x=190/10
x=19

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