(4x+39)+(6x+32)=180

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Solution for (4x+39)+(6x+32)=180 equation: 



(4x+39)+(6x+32)=180

We move all terms to the left:

(4x+39)+(6x+32)-(180)=0

We get rid of parentheses

4x+6x+39+32-180=0

We add all the numbers together, and all the variables

10x-109=0

We move all terms containing x to the left, all other terms to the right

10x=109

x=109/10

x=10+9/10

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