(4x+4)(3x-3)=0

Solution for (4x+4)(3x-3)=0 equation:

Simplifying
(4x + 4)(3x + -3) = 0

Reorder the terms:
(4 + 4x)(3x + -3) = 0

Reorder the terms:
(4 + 4x)(-3 + 3x) = 0

Multiply (4 + 4x) * (-3 + 3x)
(4(-3 + 3x) + 4x * (-3 + 3x)) = 0
((-3 * 4 + 3x * 4) + 4x * (-3 + 3x)) = 0
((-12 + 12x) + 4x * (-3 + 3x)) = 0
(-12 + 12x + (-3 * 4x + 3x * 4x)) = 0
(-12 + 12x + (-12x + 12x2)) = 0

Combine like terms: 12x + -12x = 0
(-12 + 0 + 12x2) = 0
(-12 + 12x2) = 0

Solving
-12 + 12x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 12x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 12x2 = 0 + 12
12x2 = 0 + 12

Combine like terms: 0 + 12 = 12
12x2 = 12

Divide each side by '12'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}