(4x+4)(8x+2)=162

Solution for (4x+4)(8x+2)=162 equation:

(4x+4)(8x+2)=162

We move all terms to the left:

(4x+4)(8x+2)-(162)=0

We multiply parentheses ..

(+32x^2+8x+32x+8)-162=0

We get rid of parentheses

32x^2+8x+32x+8-162=0

We add all the numbers together, and all the variables

32x^2+40x-154=0

a = 32; b = 40; c = -154;
Δ = b2-4ac
Δ = 402-4·32·(-154)
Δ = 21312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21312}=\sqrt{576*37}=\sqrt{576}*\sqrt{37}=24\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-24\sqrt{37}}{2*32}=\frac{-40-24\sqrt{37}}{64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+24\sqrt{37}}{2*32}=\frac{-40+24\sqrt{37}}{64}
$