(4x+4)(x+8)=0

Solution for (4x+4)(x+8)=0 equation:

(4x+4)(x+8)=0

We multiply parentheses ..

(+4x^2+32x+4x+32)=0

We get rid of parentheses

4x^2+32x+4x+32=0

We add all the numbers together, and all the variables

4x^2+36x+32=0

a = 4; b = 36; c = +32;
Δ = b2-4ac
Δ = 362-4·4·32
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-28}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+28}{2*4}=\frac{-8}{8}
=-1
$