(4x+4)+(3x+4)=72

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Solution for (4x+4)+(3x+4)=72 equation: 



(4x+4)+(3x+4)=72

We move all terms to the left:

(4x+4)+(3x+4)-(72)=0

We get rid of parentheses

4x+3x+4+4-72=0

We add all the numbers together, and all the variables

7x-64=0

We move all terms containing x to the left, all other terms to the right

7x=64

x=64/7

x=9+1/7

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