(4x+4)+(4x)+(4x+3)=(4x)+(5x+1)+(4x)

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Solution for (4x+4)+(4x)+(4x+3)=(4x)+(5x+1)+(4x) equation: 



(4x+4)+(4x)+(4x+3)=(4x)+(5x+1)+(4x)

We move all terms to the left:

(4x+4)+(4x)+(4x+3)-((4x)+(5x+1)+(4x))=0

We add all the numbers together, and all the variables

4x+(4x+4)+(4x+3)-(4x+(5x+1)+4x)=0

We get rid of parentheses

4x+4x+4x-(4x+(5x+1)+4x)+4+3=0



We calculate terms in parentheses: -(4x+(5x+1)+4x), so:

4x+(5x+1)+4x

We add all the numbers together, and all the variables

8x+(5x+1)

We get rid of parentheses

8x+5x+1

We add all the numbers together, and all the variables

13x+1

Back to the equation:

-(13x+1)



We add all the numbers together, and all the variables

12x-(13x+1)+7=0

We get rid of parentheses

12x-13x-1+7=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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