(4x+4)=(2x+11)

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Solution for (4x+4)=(2x+11) equation: 



(4x+4)=(2x+11)

We move all terms to the left:

(4x+4)-((2x+11))=0

We get rid of parentheses

4x-((2x+11))+4=0



We calculate terms in parentheses: -((2x+11)), so:

(2x+11)

We get rid of parentheses

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

4x-2x-11+4=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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