(4x+4)=(2x+22)

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Solution for (4x+4)=(2x+22) equation:



(4x+4)=(2x+22)
We move all terms to the left:
(4x+4)-((2x+22))=0
We get rid of parentheses
4x-((2x+22))+4=0
We calculate terms in parentheses: -((2x+22)), so:
(2x+22)
We get rid of parentheses
2x+22
Back to the equation:
-(2x+22)
We get rid of parentheses
4x-2x-22+4=0
We add all the numbers together, and all the variables
2x-18=0
We move all terms containing x to the left, all other terms to the right
2x=18
x=18/2
x=9

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