(4x+4)=(2x+22)

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Solution for (4x+4)=(2x+22) equation: 



(4x+4)=(2x+22)

We move all terms to the left:

(4x+4)-((2x+22))=0

We get rid of parentheses

4x-((2x+22))+4=0



We calculate terms in parentheses: -((2x+22)), so:

(2x+22)

We get rid of parentheses

2x+22

Back to the equation:

-(2x+22)



We get rid of parentheses

4x-2x-22+4=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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