(4x+43)+(2x-12)=180

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Solution for (4x+43)+(2x-12)=180 equation:



(4x+43)+(2x-12)=180
We move all terms to the left:
(4x+43)+(2x-12)-(180)=0
We get rid of parentheses
4x+2x+43-12-180=0
We add all the numbers together, and all the variables
6x-149=0
We move all terms containing x to the left, all other terms to the right
6x=149
x=149/6
x=24+5/6

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