(4x+43)+(9x-26)=(2x-12)

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Solution for (4x+43)+(9x-26)=(2x-12) equation: 



(4x+43)+(9x-26)=(2x-12)

We move all terms to the left:

(4x+43)+(9x-26)-((2x-12))=0

We get rid of parentheses

4x+9x-((2x-12))+43-26=0



We calculate terms in parentheses: -((2x-12)), so:

(2x-12)

We get rid of parentheses

2x-12

Back to the equation:

-(2x-12)



We add all the numbers together, and all the variables

13x-(2x-12)+17=0

We get rid of parentheses

13x-2x+12+17=0

We add all the numbers together, and all the variables

11x+29=0

We move all terms containing x to the left, all other terms to the right

11x=-29

x=-29/11

x=-2+7/11

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