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(4x+4x+x+x)+(4+2-4-2)=30
We move all terms to the left:
(4x+4x+x+x)+(4+2-4-2)-(30)=0
determiningTheFunctionDomain (4x+4x+x+x)-30+(4+2-4-2)=0
We add all the numbers together, and all the variables
(+10x)-30+0=0
We add all the numbers together, and all the variables
(+10x)-30=0
We get rid of parentheses
10x-30=0
We move all terms containing x to the left, all other terms to the right
10x=30
x=30/10
x=3
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