(4x+5)(4x-3)+(5-4x)(5+4x)=(3x-2)(3x-2)-(9x-5)(x+1)

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Solution for (4x+5)(4x-3)+(5-4x)(5+4x)=(3x-2)(3x-2)-(9x-5)(x+1) equation:



(4x+5)(4x-3)+(5-4x)(5+4x)=(3x-2)(3x-2)-(9x-5)(x+1)
We move all terms to the left:
(4x+5)(4x-3)+(5-4x)(5+4x)-((3x-2)(3x-2)-(9x-5)(x+1))=0
We add all the numbers together, and all the variables
(4x+5)(4x-3)+(-4x+5)(4x+5)-((3x-2)(3x-2)-(9x-5)(x+1))=0
We multiply parentheses ..
(+16x^2-12x+20x-15)+(-4x+5)(4x+5)-((3x-2)(3x-2)-(9x-5)(x+1))=0
We calculate terms in parentheses: -((3x-2)(3x-2)-(9x-5)(x+1)), so:
(3x-2)(3x-2)-(9x-5)(x+1)
We multiply parentheses ..
(+9x^2-6x-6x+4)-(9x-5)(x+1)
We get rid of parentheses
9x^2-6x-6x-(9x-5)(x+1)+4
We multiply parentheses ..
9x^2-(+9x^2+9x-5x-5)-6x-6x+4
We add all the numbers together, and all the variables
9x^2-(+9x^2+9x-5x-5)-12x+4
We get rid of parentheses
9x^2-9x^2-9x+5x-12x+5+4
We add all the numbers together, and all the variables
-16x+9
Back to the equation:
-(-16x+9)
We get rid of parentheses
16x^2-12x+20x+(-4x+5)(4x+5)+16x-15-9=0
We multiply parentheses ..
16x^2+(-16x^2-20x+20x+25)-12x+20x+16x-15-9=0
We add all the numbers together, and all the variables
16x^2+(-16x^2-20x+20x+25)+24x-24=0
We get rid of parentheses
16x^2-16x^2-20x+20x+24x+25-24=0
We add all the numbers together, and all the variables
24x+1=0
We move all terms containing x to the left, all other terms to the right
24x=-1
x=-1/24
x=-1/24

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