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(4x+5)(5x+5)+(2x)=180
We move all terms to the left:
(4x+5)(5x+5)+(2x)-(180)=0
We add all the numbers together, and all the variables
2x+(4x+5)(5x+5)-180=0
We multiply parentheses ..
(+20x^2+20x+25x+25)+2x-180=0
We get rid of parentheses
20x^2+20x+25x+2x+25-180=0
We add all the numbers together, and all the variables
20x^2+47x-155=0
a = 20; b = 47; c = -155;
Δ = b2-4ac
Δ = 472-4·20·(-155)
Δ = 14609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{14609}}{2*20}=\frac{-47-\sqrt{14609}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{14609}}{2*20}=\frac{-47+\sqrt{14609}}{40} $
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