(4x+5)(x+2)=x

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Solution for (4x+5)(x+2)=x equation: 



(4x+5)(x+2)=x

We move all terms to the left:

(4x+5)(x+2)-(x)=0

We add all the numbers together, and all the variables

-1x+(4x+5)(x+2)=0

We multiply parentheses ..

(+4x^2+8x+5x+10)-1x=0

We get rid of parentheses

4x^2+8x+5x-1x+10=0

We add all the numbers together, and all the variables

4x^2+12x+10=0

a = 4; b = 12; c = +10;
Δ = b2-4ac
Δ = 122-4·4·10
Δ = -16
Delta is less than zero, so there is no solution for the equation

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