(4x+5)+(3x+6)=4x+(5+3x)+6

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Solution for (4x+5)+(3x+6)=4x+(5+3x)+6 equation: 



(4x+5)+(3x+6)=4x+(5+3x)+6

We move all terms to the left:

(4x+5)+(3x+6)-(4x+(5+3x)+6)=0

We add all the numbers together, and all the variables

(4x+5)+(3x+6)-(4x+(3x+5)+6)=0

We get rid of parentheses

4x+3x-(4x+(3x+5)+6)+5+6=0



We calculate terms in parentheses: -(4x+(3x+5)+6), so:

4x+(3x+5)+6

We get rid of parentheses

4x+3x+5+6

We add all the numbers together, and all the variables

7x+11

Back to the equation:

-(7x+11)



We add all the numbers together, and all the variables

7x-(7x+11)+11=0

We get rid of parentheses

7x-7x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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