(4x+5)+(3x+8)=(8x-4)

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Solution for (4x+5)+(3x+8)=(8x-4) equation: 



(4x+5)+(3x+8)=(8x-4)

We move all terms to the left:

(4x+5)+(3x+8)-((8x-4))=0

We get rid of parentheses

4x+3x-((8x-4))+5+8=0



We calculate terms in parentheses: -((8x-4)), so:

(8x-4)

We get rid of parentheses

8x-4

Back to the equation:

-(8x-4)



We add all the numbers together, and all the variables

7x-(8x-4)+13=0

We get rid of parentheses

7x-8x+4+13=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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