(4x+5)+(4x+4)+(4x)=(4x)+(4x)+(5x+6)

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Solution for (4x+5)+(4x+4)+(4x)=(4x)+(4x)+(5x+6) equation: 



(4x+5)+(4x+4)+(4x)=(4x)+(4x)+(5x+6)

We move all terms to the left:

(4x+5)+(4x+4)+(4x)-((4x)+(4x)+(5x+6))=0

We add all the numbers together, and all the variables

4x+(4x+5)+(4x+4)-(4x+4x+(5x+6))=0

We get rid of parentheses

4x+4x+4x-(4x+4x+(5x+6))+5+4=0



We calculate terms in parentheses: -(4x+4x+(5x+6)), so:

4x+4x+(5x+6)

We add all the numbers together, and all the variables

8x+(5x+6)

We get rid of parentheses

8x+5x+6

We add all the numbers together, and all the variables

13x+6

Back to the equation:

-(13x+6)



We add all the numbers together, and all the variables

12x-(13x+6)+9=0

We get rid of parentheses

12x-13x-6+9=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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