(4x+5)+(5x-5)+(6x=10)+(4x+10)

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Solution for (4x+5)+(5x-5)+(6x=10)+(4x+10) equation: 



(4x+5)+(5x-5)+(6x=10)+(4x+10)

We move all terms to the left:

(4x+5)+(5x-5)+(6x-(10)+(4x+10))=0

We get rid of parentheses

4x+5x+(6x-10+(4x+10))+5-5=0



We calculate terms in parentheses: +(6x-10+(4x+10)), so:

6x-10+(4x+10)

determiningTheFunctionDomain
6x+(4x+10)-10

We get rid of parentheses

6x+4x+10-10

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)



We add all the numbers together, and all the variables

19x=0

x=0/19

x=0

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