(4x+5)+(9x+1)=162

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Solution for (4x+5)+(9x+1)=162 equation: 



(4x+5)+(9x+1)=162

We move all terms to the left:

(4x+5)+(9x+1)-(162)=0

We get rid of parentheses

4x+9x+5+1-162=0

We add all the numbers together, and all the variables

13x-156=0

We move all terms containing x to the left, all other terms to the right

13x=156

x=156/13

x=12

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