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(4x+5)/(4-2x)=9/2
We move all terms to the left:
(4x+5)/(4-2x)-(9/2)=0
Domain of the equation: (4-2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-2x!=-4
x!=-4/-2
x!=+2
x∈R
(4x+5)/(-2x+4)-(+9/2)=0
We get rid of parentheses
(4x+5)/(-2x+4)-9/2=0
We calculate fractions
(8x+10)/(-4x+8)+(18x-36)/(-4x+8)=0
We multiply all the terms by the denominator
(8x+10)+(18x-36)=0
We get rid of parentheses
8x+18x+10-36=0
We add all the numbers together, and all the variables
26x-26=0
We move all terms containing x to the left, all other terms to the right
26x=26
x=26/26
x=1
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