(4x+5)/5=(2x+7)/7

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Solution for (4x+5)/5=(2x+7)/7 equation: 



(4x+5)/5=(2x+7)/7

We move all terms to the left:

(4x+5)/5-((2x+7)/7)=0

We calculate fractions


4x/()+(-((2x+7)*5)/()=0



We calculate terms in parentheses: +(-((2x+7)*5)/(), so:

-((2x+7)*5)/(

We multiply all the terms by the denominator


-((2x+7)*5)



We calculate terms in parentheses: -((2x+7)*5), so:

(2x+7)*5

We multiply parentheses

10x+35

Back to the equation:

-(10x+35)



We get rid of parentheses

-10x-35

Back to the equation:

+(-10x-35)



We get rid of parentheses

4x/()-10x-35=0

We multiply all the terms by the denominator


4x-10x*()-35*()=0

We add all the numbers together, and all the variables

4x-10x*()=0

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