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(4x+5)/6x-1=3+2x/3x-4
We move all terms to the left:
(4x+5)/6x-1-(3+2x/3x-4)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x-4)!=0We add all the numbers together, and all the variables
x∈R
(4x+5)/6x-(2x/3x-1)-1=0
We get rid of parentheses
(4x+5)/6x-2x/3x+1-1=0
We calculate fractions
(-12x^2)/18x^2+(12x^2+15x)/18x^2+1-1=0
We add all the numbers together, and all the variables
(-12x^2)/18x^2+(12x^2+15x)/18x^2=0
We multiply all the terms by the denominator
(-12x^2)+(12x^2+15x)=0
We get rid of parentheses
-12x^2+12x^2+15x=0
We add all the numbers together, and all the variables
15x=0
x=0/15
x=0
Równanie nie ma rozwiązania
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