(4x+5)2-80x=(4x-5)2

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Solution for (4x+5)2-80x=(4x-5)2 equation:



(4x+5)2-80x=(4x-5)2
We move all terms to the left:
(4x+5)2-80x-((4x-5)2)=0
We add all the numbers together, and all the variables
-80x+(4x+5)2-((4x-5)2)=0
We multiply parentheses
-80x+8x-((4x-5)2)+10=0
We calculate terms in parentheses: -((4x-5)2), so:
(4x-5)2
We multiply parentheses
8x-10
Back to the equation:
-(8x-10)
We add all the numbers together, and all the variables
-72x-(8x-10)+10=0
We get rid of parentheses
-72x-8x+10+10=0
We add all the numbers together, and all the variables
-80x+20=0
We move all terms containing x to the left, all other terms to the right
-80x=-20
x=-20/-80
x=1/4

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