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(4x+5)x+41=180
We move all terms to the left:
(4x+5)x+41-(180)=0
We add all the numbers together, and all the variables
(4x+5)x-139=0
We multiply parentheses
4x^2+5x-139=0
a = 4; b = 5; c = -139;
Δ = b2-4ac
Δ = 52-4·4·(-139)
Δ = 2249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{2249}}{2*4}=\frac{-5-\sqrt{2249}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{2249}}{2*4}=\frac{-5+\sqrt{2249}}{8} $
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