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(4x+5)x=80
We move all terms to the left:
(4x+5)x-(80)=0
We multiply parentheses
4x^2+5x-80=0
a = 4; b = 5; c = -80;
Δ = b2-4ac
Δ = 52-4·4·(-80)
Δ = 1305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1305}=\sqrt{9*145}=\sqrt{9}*\sqrt{145}=3\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{145}}{2*4}=\frac{-5-3\sqrt{145}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{145}}{2*4}=\frac{-5+3\sqrt{145}}{8} $
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