(4x+50)=(3x-15)

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Solution for (4x+50)=(3x-15) equation: 



(4x+50)=(3x-15)

We move all terms to the left:

(4x+50)-((3x-15))=0

We get rid of parentheses

4x-((3x-15))+50=0



We calculate terms in parentheses: -((3x-15)), so:

(3x-15)

We get rid of parentheses

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

4x-3x+15+50=0

We add all the numbers together, and all the variables

x+65=0

We move all terms containing x to the left, all other terms to the right

x=-65

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