(4x+57)+35=(2x+96)

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Solution for (4x+57)+35=(2x+96) equation: 



(4x+57)+35=(2x+96)

We move all terms to the left:

(4x+57)+35-((2x+96))=0

We get rid of parentheses

4x-((2x+96))+57+35=0



We calculate terms in parentheses: -((2x+96)), so:

(2x+96)

We get rid of parentheses

2x+96

Back to the equation:

-(2x+96)



We add all the numbers together, and all the variables

4x-(2x+96)+92=0

We get rid of parentheses

4x-2x-96+92=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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