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(4x+6)(4x+6)-270=0
We multiply parentheses ..
(+16x^2+24x+24x+36)-270=0
We get rid of parentheses
16x^2+24x+24x+36-270=0
We add all the numbers together, and all the variables
16x^2+48x-234=0
a = 16; b = 48; c = -234;
Δ = b2-4ac
Δ = 482-4·16·(-234)
Δ = 17280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17280}=\sqrt{576*30}=\sqrt{576}*\sqrt{30}=24\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-24\sqrt{30}}{2*16}=\frac{-48-24\sqrt{30}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+24\sqrt{30}}{2*16}=\frac{-48+24\sqrt{30}}{32} $
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