(4x+6)+(11-6)=180

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Solution for (4x+6)+(11-6)=180 equation: 



(4x+6)+(11-6)=180

We move all terms to the left:

(4x+6)+(11-6)-(180)=0

determiningTheFunctionDomain
(4x+6)-180+(11-6)=0

We add all the numbers together, and all the variables

(4x+6)-180+5=0

We add all the numbers together, and all the variables

(4x+6)-175=0

We get rid of parentheses

4x+6-175=0

We add all the numbers together, and all the variables

4x-169=0

We move all terms containing x to the left, all other terms to the right

4x=169

x=169/4

x=42+1/4

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