(4x+6)x-3=92

Solution for (4x+6)x-3=92 equation:

(4x+6)x-3=92

We move all terms to the left:

(4x+6)x-3-(92)=0

We add all the numbers together, and all the variables

(4x+6)x-95=0

We multiply parentheses

4x^2+6x-95=0

a = 4; b = 6; c = -95;
Δ = b2-4ac
Δ = 62-4·4·(-95)
Δ = 1556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1556}=\sqrt{4*389}=\sqrt{4}*\sqrt{389}=2\sqrt{389}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{389}}{2*4}=\frac{-6-2\sqrt{389}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{389}}{2*4}=\frac{-6+2\sqrt{389}}{8}
$