(4x+6-3x)-(2x+4)=3(x-6)

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Solution for (4x+6-3x)-(2x+4)=3(x-6) equation: 



(4x+6-3x)-(2x+4)=3(x-6)

We move all terms to the left:

(4x+6-3x)-(2x+4)-(3(x-6))=0

We add all the numbers together, and all the variables

(x+6)-(2x+4)-(3(x-6))=0

We get rid of parentheses

x-2x-(3(x-6))+6-4=0



We calculate terms in parentheses: -(3(x-6)), so:

3(x-6)

We multiply parentheses

3x-18

Back to the equation:

-(3x-18)



We add all the numbers together, and all the variables

-1x-(3x-18)+2=0

We get rid of parentheses

-1x-3x+18+2=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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