(4x+68)-(15x-35)=-40

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Solution for (4x+68)-(15x-35)=-40 equation: 



(4x+68)-(15x-35)=-40

We move all terms to the left:

(4x+68)-(15x-35)-(-40)=0

We add all the numbers together, and all the variables

(4x+68)-(15x-35)+40=0

We get rid of parentheses

4x-15x+68+35+40=0

We add all the numbers together, and all the variables

-11x+143=0

We move all terms containing x to the left, all other terms to the right

-11x=-143

x=-143/-11

x=+13

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