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(4x+7)(3x-10)=0
We multiply parentheses ..
(+12x^2-40x+21x-70)=0
We get rid of parentheses
12x^2-40x+21x-70=0
We add all the numbers together, and all the variables
12x^2-19x-70=0
a = 12; b = -19; c = -70;
Δ = b2-4ac
Δ = -192-4·12·(-70)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-61}{2*12}=\frac{-42}{24} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+61}{2*12}=\frac{80}{24} =3+1/3 $
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