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(4x+7)(5x-3)=180
We move all terms to the left:
(4x+7)(5x-3)-(180)=0
We multiply parentheses ..
(+20x^2-12x+35x-21)-180=0
We get rid of parentheses
20x^2-12x+35x-21-180=0
We add all the numbers together, and all the variables
20x^2+23x-201=0
a = 20; b = 23; c = -201;
Δ = b2-4ac
Δ = 232-4·20·(-201)
Δ = 16609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{16609}}{2*20}=\frac{-23-\sqrt{16609}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{16609}}{2*20}=\frac{-23+\sqrt{16609}}{40} $
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