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(4x+7)(5x-9)=0
We multiply parentheses ..
(+20x^2-36x+35x-63)=0
We get rid of parentheses
20x^2-36x+35x-63=0
We add all the numbers together, and all the variables
20x^2-1x-63=0
a = 20; b = -1; c = -63;
Δ = b2-4ac
Δ = -12-4·20·(-63)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5041}=71$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-71}{2*20}=\frac{-70}{40} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+71}{2*20}=\frac{72}{40} =1+4/5 $
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