(4x+7)(5x-9)=0

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Solution for (4x+7)(5x-9)=0 equation:



(4x+7)(5x-9)=0
We multiply parentheses ..
(+20x^2-36x+35x-63)=0
We get rid of parentheses
20x^2-36x+35x-63=0
We add all the numbers together, and all the variables
20x^2-1x-63=0
a = 20; b = -1; c = -63;
Δ = b2-4ac
Δ = -12-4·20·(-63)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-71}{2*20}=\frac{-70}{40} =-1+3/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+71}{2*20}=\frac{72}{40} =1+4/5 $

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