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(4x+7)(7x-3)=180
We move all terms to the left:
(4x+7)(7x-3)-(180)=0
We multiply parentheses ..
(+28x^2-12x+49x-21)-180=0
We get rid of parentheses
28x^2-12x+49x-21-180=0
We add all the numbers together, and all the variables
28x^2+37x-201=0
a = 28; b = 37; c = -201;
Δ = b2-4ac
Δ = 372-4·28·(-201)
Δ = 23881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{23881}}{2*28}=\frac{-37-\sqrt{23881}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{23881}}{2*28}=\frac{-37+\sqrt{23881}}{56} $
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