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(4x+7)(x-9)=0
We multiply parentheses ..
(+4x^2-36x+7x-63)=0
We get rid of parentheses
4x^2-36x+7x-63=0
We add all the numbers together, and all the variables
4x^2-29x-63=0
a = 4; b = -29; c = -63;
Δ = b2-4ac
Δ = -292-4·4·(-63)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-43}{2*4}=\frac{-14}{8} =-1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+43}{2*4}=\frac{72}{8} =9 $
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