(4x+7)+(4x+2)+(4x)=(4x)+(4x)+(5x+8)

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Solution for (4x+7)+(4x+2)+(4x)=(4x)+(4x)+(5x+8) equation: 



(4x+7)+(4x+2)+(4x)=(4x)+(4x)+(5x+8)

We move all terms to the left:

(4x+7)+(4x+2)+(4x)-((4x)+(4x)+(5x+8))=0

We add all the numbers together, and all the variables

4x+(4x+7)+(4x+2)-(4x+4x+(5x+8))=0

We get rid of parentheses

4x+4x+4x-(4x+4x+(5x+8))+7+2=0



We calculate terms in parentheses: -(4x+4x+(5x+8)), so:

4x+4x+(5x+8)

We add all the numbers together, and all the variables

8x+(5x+8)

We get rid of parentheses

8x+5x+8

We add all the numbers together, and all the variables

13x+8

Back to the equation:

-(13x+8)



We add all the numbers together, and all the variables

12x-(13x+8)+9=0

We get rid of parentheses

12x-13x-8+9=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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