(4x+8)(4x+10)=440

Solution for (4x+8)(4x+10)=440 equation:

(4x+8)(4x+10)=440

We move all terms to the left:

(4x+8)(4x+10)-(440)=0

We multiply parentheses ..

(+16x^2+40x+32x+80)-440=0

We get rid of parentheses

16x^2+40x+32x+80-440=0

We add all the numbers together, and all the variables

16x^2+72x-360=0

a = 16; b = 72; c = -360;
Δ = b2-4ac
Δ = 722-4·16·(-360)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-168}{2*16}=\frac{-240}{32}
=-7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+168}{2*16}=\frac{96}{32}
=3
$