(4x+8)(4x+8)+(3x-5)(3x-5)=(5x+5)(5x+5)

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Solution for (4x+8)(4x+8)+(3x-5)(3x-5)=(5x+5)(5x+5) equation:



(4x+8)(4x+8)+(3x-5)(3x-5)=(5x+5)(5x+5)
We move all terms to the left:
(4x+8)(4x+8)+(3x-5)(3x-5)-((5x+5)(5x+5))=0
We multiply parentheses ..
(+16x^2+32x+32x+64)+(3x-5)(3x-5)-((5x+5)(5x+5))=0
We calculate terms in parentheses: -((5x+5)(5x+5)), so:
(5x+5)(5x+5)
We multiply parentheses ..
(+25x^2+25x+25x+25)
We get rid of parentheses
25x^2+25x+25x+25
We add all the numbers together, and all the variables
25x^2+50x+25
Back to the equation:
-(25x^2+50x+25)
We get rid of parentheses
16x^2-25x^2+32x+32x+(3x-5)(3x-5)-50x+64-25=0
We multiply parentheses ..
16x^2-25x^2+(+9x^2-15x-15x+25)+32x+32x-50x+64-25=0
We add all the numbers together, and all the variables
-9x^2+(+9x^2-15x-15x+25)+14x+39=0
We get rid of parentheses
-9x^2+9x^2-15x-15x+14x+25+39=0
We add all the numbers together, and all the variables
-16x+64=0
We move all terms containing x to the left, all other terms to the right
-16x=-64
x=-64/-16
x=+4

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