(4x+8)+(3x-4)=32

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Solution for (4x+8)+(3x-4)=32 equation: 



(4x+8)+(3x-4)=32

We move all terms to the left:

(4x+8)+(3x-4)-(32)=0

We get rid of parentheses

4x+3x+8-4-32=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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