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(4x+9)(3x+4)=0
We multiply parentheses ..
(+12x^2+16x+27x+36)=0
We get rid of parentheses
12x^2+16x+27x+36=0
We add all the numbers together, and all the variables
12x^2+43x+36=0
a = 12; b = 43; c = +36;
Δ = b2-4ac
Δ = 432-4·12·36
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-11}{2*12}=\frac{-54}{24} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+11}{2*12}=\frac{-32}{24} =-1+1/3 $
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