(4x+9)x=440

Solution for (4x+9)x=440 equation:

(4x+9)x=440

We move all terms to the left:

(4x+9)x-(440)=0

We multiply parentheses

4x^2+9x-440=0

a = 4; b = 9; c = -440;
Δ = b2-4ac
Δ = 92-4·4·(-440)
Δ = 7121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{7121}}{2*4}=\frac{-9-\sqrt{7121}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{7121}}{2*4}=\frac{-9+\sqrt{7121}}{8}
$