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(4x+)=(3x+33)
We move all terms to the left:
(4x+)-((3x+33))=0
We add all the numbers together, and all the variables
(+4x)-((3x+33))=0
We get rid of parentheses
4x-((3x+33))=0
We calculate terms in parentheses: -((3x+33)), so:We get rid of parentheses
(3x+33)
We get rid of parentheses
3x+33
Back to the equation:
-(3x+33)
4x-3x-33=0
We add all the numbers together, and all the variables
x-33=0
We move all terms containing x to the left, all other terms to the right
x=33
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