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(4x-1)(2x+8)=0
We multiply parentheses ..
(+8x^2+32x-2x-8)=0
We get rid of parentheses
8x^2+32x-2x-8=0
We add all the numbers together, and all the variables
8x^2+30x-8=0
a = 8; b = 30; c = -8;
Δ = b2-4ac
Δ = 302-4·8·(-8)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{1156}=34x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-34}{2*8}=\frac{-64}{16} =-4x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+34}{2*8}=\frac{4}{16} =1/4
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