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(4x-1)(3-11x)=0
We add all the numbers together, and all the variables
(4x-1)(-11x+3)=0
We multiply parentheses ..
(-44x^2+12x+11x-3)=0
We get rid of parentheses
-44x^2+12x+11x-3=0
We add all the numbers together, and all the variables
-44x^2+23x-3=0
a = -44; b = 23; c = -3;
Δ = b2-4ac
Δ = 232-4·(-44)·(-3)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-1}{2*-44}=\frac{-24}{-88} =3/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+1}{2*-44}=\frac{-22}{-88} =1/4 $
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